JEE Rank Predictor (India)

Enter your JEE Main percentile or marks along with your category and course preference to get a predicted All India Rank (AIR). The JEE Rank Predictor estimates your rank range based on historical percentile-to-rank data, helping you gauge which NITs, IIITs, and top government colleges fall within your reach before counselling begins.

Enter your NTA percentile score (0 to 100)

Enter your raw score out of 300

Results

Predicted AIR (General)

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Best Case Rank

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Worst Case Rank

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Estimated Category Rank

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Expected College Tier

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Rank Range Breakdown

Results Table

Frequently Asked Questions

How does the JEE Main rank predictor work?

The predictor uses historical NTA data mapping percentile scores to All India Ranks. It applies a statistical formula: Rank ≈ (1 – Percentile/100) × Total Candidates. Category-wise multipliers are then applied based on seat reservation norms to estimate your category rank alongside the general AIR.

Can I predict my JEE rank from marks instead of percentile?

Yes. Enter your raw score out of 300 and select 'Marks' as the input mode. The tool converts your marks to an approximate percentile using historical marks-vs-percentile data from previous JEE Main sessions, then estimates your rank. Note that the percentile-to-rank route is more accurate since NTA normalises scores across sessions.

How many candidates appear in JEE Main each year?

Approximately 11–12 lakh (1.1–1.2 million) candidates appear in JEE Main annually across both sessions. The rank is computed against the total unique registered candidates, so the formula uses ~11,00,000 as the base for 2025–26 predictions.

What is the difference between JEE Main rank and JEE Advanced rank?

JEE Main rank (AIR) determines admission to NITs, IIITs, and GFTIs via JoSAA counselling. Only the top 2,50,000 JEE Main qualifiers are eligible to appear for JEE Advanced, which is the gateway to IITs. This tool predicts your JEE Main AIR; a separate JEE Advanced rank predictor is needed for IIT predictions.

Which category has the most lenient cutoff for JEE Main?

ST (Scheduled Tribe) candidates generally have the most lenient cutoffs, followed by SC, OBC-NCL, EWS, and then General. Category rank estimates in this tool use approximate seat-reservation multipliers: OBC-NCL ~27%, SC ~15%, ST ~7.5%, EWS ~10% of total seats.

What JEE Main rank is needed to get into an NIT?

For top NITs like NIT Trichy, NIT Warangal, or NIT Surathkal, a General category rank below 5,000–10,000 is typically required for CS/ECE branches. For less competitive branches at lower-ranked NITs, ranks up to 50,000–75,000 may suffice. OBC/SC/ST candidates have proportionally relaxed cutoffs.

How accurate is this JEE rank predictor?

The prediction is based on historical trends and the standard NTA rank formula. Accuracy is typically within ±5–10% of the actual rank for percentiles above 80. However, the actual rank can vary due to factors like total candidates in a specific year, paper difficulty, and normalisation across shifts. Treat this as an estimate, not a guarantee.

What is the JEE Main cutoff percentile to qualify for JEE Advanced?

The qualifying cutoff percentile for JEE Advanced eligibility varies by category. In recent years, General category candidates needed around 89–93 percentile, OBC-NCL around 74–80, SC around 54–60, and ST around 44–54. These thresholds shift each year depending on the difficulty of the exam and number of candidates.

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