Car Jump Distance Calculator

Enter your initial velocity, launch angle, and ramp height to simulate a car jump. The Car Jump Distance Calculator computes horizontal jump distance, maximum height, air time, and estimated landing angle using projectile physics with optional air drag. Adjust car mass and drag coefficient to model real-world conditions.

m/s

Speed of the car at the moment of take-off

°

Angle of the take-off ramp relative to horizontal

m

Vertical height of the take-off ramp above the ground

m

Vertical height of the landing surface relative to take-off ground level

m/s²

Standard Earth gravity is 9.81 m/s²

kg

Typical passenger car is around 1200–1600 kg

Typical cars range from 0.25 to 0.45

Approximate cross-sectional area facing the direction of motion

kg/m³

Standard sea-level air density is 1.225 kg/m³

Results

Jump Distance

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Maximum Height Reached

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Air Time

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Landing Angle

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Landing Speed

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Peak Height Above Take-off Point

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Car Jump Trajectory

Results Table

Frequently Asked Questions

What is car jump distance?

Car jump distance is the horizontal distance a car travels while airborne after launching off a ramp. It depends on the car's take-off speed, ramp angle, ramp height, and landing surface height. In stunt driving and movie productions, accurately predicting this distance is critical for safety.

How is car jump distance calculated?

The basic formula is D = (v² × sin(2θ)) / g for a flat launch and landing. When ramp heights differ, you solve the full projectile equations: x(t) = v·cos(θ)·t and y(t) = h₀ + v·sin(θ)·t − ½g·t². Air drag adds a velocity-dependent deceleration force F = ½·ρ·Cd·A·v², which reduces both range and peak height.

Why does a car tilt during a jump?

When a car leaves a ramp, the front wheels lift off first and lose contact with the surface, removing the normal force. The engine torque, angular momentum of spinning wheels, and the car's own moment of inertia cause the body to rotate about its center of mass. The rate of rotation depends on the net torque and the car's moment of inertia.

What does the landing angle mean?

The landing angle is the angle of the car's velocity vector below the horizontal at the moment it touches the landing surface. A steep landing angle (e.g., 45°+) puts more stress on the suspension and increases the risk of nose-diving. Stunt drivers aim for landing angles under 20–25° for a safer, flatter touchdown.

How does air drag affect jump distance?

Air drag creates a force opposing the car's motion proportional to the square of its speed, the drag coefficient, frontal area, and air density. This continuously reduces horizontal velocity and slightly alters vertical deceleration, shortening the jump distance compared to an ideal no-drag projectile. At typical stunt speeds (60–120 km/h), the effect can reduce range by 5–15%.

What should I know before attempting a car jump?

Car jumps are extremely dangerous and should only be performed by trained professional stunt drivers with proper safety equipment, medical personnel on site, and extensively engineered ramps. Even small deviations in speed or ramp alignment can result in catastrophic outcomes. This calculator is intended for educational and cinematic planning purposes only.

How can I approximate a car's moment of inertia?

A rough estimate treats the car as a rectangular box: I ≈ (m/12)·(L² + H²), where m is mass, L is car length, and H is car height. More accurate values require detailed mass distribution data. For a typical 1400 kg passenger car (4.5 m long, 1.5 m tall), I ≈ roughly 3,800–5,000 kg·m².

What is the optimal launch angle for maximum jump distance?

For a flat landing at the same height as the take-off, the theoretical optimum is 45°. However, when landing is lower than the take-off (as is common in stunts), the optimal angle is less than 45°. When considering air drag, the optimal angle drops slightly further, typically to around 38–43° depending on speed and drag parameters.

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