Thermal Stress Calculator

Calculate the thermal stress developed in a constrained material when its temperature changes. Enter the material's Young's Modulus (E), coefficient of thermal expansion (α), initial temperature (T₀), and final temperature (T₁) — and get the resulting thermal stress (σ) using the formula σ = E × α × ΔT. Choose a preset material to auto-fill properties, or enter custom values for any material.

Select a material to auto-fill E and α values, or choose Custom to enter your own.

GPa

Modulus of elasticity of the material. Steel ≈ 200 GPa, Aluminum ≈ 69 GPa.

×10⁻⁶/°C

Linear coefficient of thermal expansion. Steel ≈ 12 ×10⁻⁶/°C, Aluminum ≈ 23 ×10⁻⁶/°C.

°C

Starting temperature of the material.

°C

Final temperature after heating or cooling.

Results

Thermal Stress (σ)

--

Temperature Change (ΔT)

--

Thermal Strain (ε = α × ΔT)

--

Stress Type

--

Stress Component Breakdown

Frequently Asked Questions

What is thermal stress?

Thermal stress is the internal stress developed in a material when it is heated or cooled and is prevented (fully or partially) from freely expanding or contracting. It arises because the material wants to change dimensions due to temperature change, but constraints from surrounding structures resist that movement. Common examples include stress in railway tracks, pipelines, concrete pavements, and engine components.

How do I calculate thermal stress?

Thermal stress is calculated using the formula σ = E × α × ΔT, where E is the material's Young's Modulus (Pa or GPa), α is the linear coefficient of thermal expansion (per °C or per °F), and ΔT is the temperature change (T₁ − T₀). This formula applies to a fully constrained bar or rod — if the material is free to expand, no stress is generated.

What is the difference between thermal stress and thermal strain?

Thermal strain (ε) is the fractional deformation a material would undergo if free to expand: ε = α × ΔT. Thermal stress (σ) is the stress that develops when that free deformation is prevented by constraints: σ = E × ε = E × α × ΔT. Strain is dimensionless, while stress has units of pressure (Pa, MPa, psi).

What factors affect thermal stress?

Three key factors govern thermal stress: (1) Young's Modulus (E) — stiffer materials develop higher stress for the same strain; (2) the coefficient of thermal expansion (α) — materials with higher α expand more and thus experience greater stress when constrained; and (3) the temperature change (ΔT) — larger temperature swings produce proportionally higher stress.

Is thermal stress tensile or compressive?

It depends on the direction of temperature change. When a material is heated (positive ΔT), it wants to expand; if constrained, compressive stress develops. When cooled (negative ΔT), it wants to contract; if constrained, tensile stress develops. This is why concrete sidewalks crack in winter and railroad tracks buckle in summer heat.

What are some real-world examples of thermal stress problems?

Thermal stress is encountered in many engineering applications: railway tracks can buckle in summer heat, concrete roads develop cracks if expansion joints are absent, boilers and pressure vessels experience cyclic stress during start-up and shutdown, glass windows can crack from uneven solar heating, and turbine blades in jet engines must withstand extreme thermal gradients.

What is the coefficient of thermal expansion and where can I find it?

The coefficient of thermal expansion (α) quantifies how much a material expands per unit length per degree of temperature rise, typically expressed in units of 10⁻⁶/°C. Common values: steel ≈ 12, aluminum ≈ 23, copper ≈ 17, concrete ≈ 10–12, glass ≈ 8–9 (all ×10⁻⁶/°C). Values are found in material data sheets, engineering handbooks, or standard references like ASTM and ASM.

Does this formula apply to all materials and geometries?

The formula σ = E × α × ΔT applies strictly to a fully constrained, homogeneous, isotropic bar or rod undergoing uniform temperature change within the elastic range. For partially constrained structures, more complex analyses are needed. For anisotropic materials (like composites), directional coefficients must be used. For large temperature changes, non-linear material behavior may need to be considered.

More Physics Tools